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Math: Advanced Math

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SAT Math — Advanced Math Quick Reference

Core Concepts

Quadratics — Three Forms

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Key quadratic tools:

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Converting to vertex form: Complete the square: y = ax² + bx + c → y = a(x − h)² + k where h = −b/(2a) and k = f(h)

Exponential Functions

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FormEquationWhat You Get Directly
Standardax² + bx + cY-intercept (c); direction (a sign)
Factoreda(x − r)(x − s)Roots r and s; x-intercepts
Vertexa(x − h)² + kVertex (h, k); axis of symmetry x = h
ToolFormulaUse
FactoringFind numbers: multiply to ac, add to bWhen it factors cleanly
Quadratic formulax = (−b ± √(b²−4ac)) / 2aAlways works
Vertex x-coordinatex = −b/(2a)From standard form
Discriminantb² − 4acPositive → 2 solutions; zero → 1; negative → 0 real
RuleFormula
General formy = a · bˣ
a = initial valuey-value when x = 0
Growth (b > 1)b = 1 + growth rate
Decay (0 < b < 1)b = 1 − decay rate
Quick percent ↔ growth factor conversions:
  • Grows 20% each year → b = 1.20
  • Decays 15% each year → b = 0.85
  • Doubles → b = 2
  • Halves → b = 0.5

Linear vs. exponential test:

  • Add same amount each step → linear
  • Multiply by same factor each step → exponential

Polynomials and Function Notation

Operations:

  • Add/subtract → combine like terms
  • Multiply → distribute (FOIL for binomials)

FOIL: (a + b)(c + d) = ac + ad + bc + bd

Function notation:

  • f(3) → substitute x = 3 wherever you see x
  • f(g(x)) → apply g first, then f to the result

Zeros/roots: Set factored polynomial = 0; solve each factor Degree = number of roots (counting multiplicity)

Common Exam Traps

  • Vertex form sign: y = a(x − 2)² + 5 has vertex at (2, 5), NOT (−2, 5)
  • Discriminant negative: No REAL solutions (there are complex solutions, but SAT cares about real)
  • Factored form zeros: (x − r) → zero is r (positive); (x + s) → zero is −s (negative)
  • Exponential growth factor: A 30% increase means b = 1.30, not 0.30
  • f(g(x)) order: Apply g FIRST, then f — not the other way around
  • Parallel lines in quadratics: Two quadratics with the same a and b but different c → same vertex x-coord, different vertex height
  • Finding b from two exponential points: Use point (0, a) to find a, then substitute the second point to find b

Aligned to the College Board Digital SAT specifications.

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